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120220121112120 = 23325333944780867
BaseRepresentation
bin11011010101011011101101…
…100111010001111000111000
3120202122221010221111010021200
4123111123231213101320320
5111224141302001041440
61103404210004134200
734215421446600501
oct3325335547217070
9522587127433250
10120220121112120
1135340081265797
121159756b397360
13521092a249943
142198983561ba8
15dd73042bac30
hex6d56ed9d1e38

120220121112120 has 48 divisors (see below), whose sum is σ = 390715393615560. Its totient is φ = 32058698963136.

The previous prime is 120220121112073. The next prime is 120220121112121. The reversal of 120220121112120 is 21211121022021.

120220121112120 is a `hidden beast` number, since 1 + 20 + 220 + 1 + 211 + 1 + 212 + 0 = 666.

It is a super-2 number, since 2×1202201211121202 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 120220121112093 and 120220121112102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120220121112121) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 166972390074 + ... + 166972390793.

Almost surely, 2120220121112120 is an apocalyptic number.

120220121112120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

120220121112120 is an abundant number, since it is smaller than the sum of its proper divisors (270495272503440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120220121112120 is a wasteful number, since it uses less digits than its factorization.

120220121112120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 333944780884 (or 333944780877 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 18.

Adding to 120220121112120 its reverse (21211121022021), we get a palindrome (141431242134141).

Subtracting from 120220121112120 its reverse (21211121022021), we obtain a palindrome (99009000090099).

The spelling of 120220121112120 in words is "one hundred twenty trillion, two hundred twenty billion, one hundred twenty-one million, one hundred twelve thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 18 20 24 30 36 40 45 60 72 90 120 180 360 333944780867 667889561734 1001834342601 1335779123468 1669723904335 2003668685202 2671558246936 3005503027803 3339447808670 4007337370404 5009171713005 6011006055606 6678895617340 8014674740808 10018343426010 12022012111212 13357791234680 15027515139015 20036686852020 24044024222424 30055030278030 40073373704040 60110060556060 120220121112120