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120421201300110 = 23251338013347779
BaseRepresentation
bin11011011000010110111110…
…111011010100101010001110
3120210101011011120100001010200
4123120112332323110222032
5111240440110013100420
61104040423002314330
734236100425153564
oct3330267673245216
9523334146301120
10120421201300110
113540838783a137
121160a5287b89a6
1352268942a0ab9
1421a45baca5a34
15ddc6724b0b90
hex6d85beed4a8e

120421201300110 has 24 divisors (see below), whose sum is σ = 313095123380520. Its totient is φ = 32112320346672.

The previous prime is 120421201300093. The next prime is 120421201300111. The reversal of 120421201300110 is 11003102124021.

120421201300110 is a `hidden beast` number, since 1 + 2 + 0 + 421 + 2 + 0 + 130 + 0 + 110 = 666.

It is a super-2 number, since 2×1204212013001102 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120421201300111) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 669006673800 + ... + 669006673979.

It is an arithmetic number, because the mean of its divisors is an integer number (13045630140855).

Almost surely, 2120421201300110 is an apocalyptic number.

120421201300110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

120421201300110 is an abundant number, since it is smaller than the sum of its proper divisors (192673922080410).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120421201300110 is a wasteful number, since it uses less digits than its factorization.

120421201300110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1338013347792 (or 1338013347789 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 120421201300110 its reverse (11003102124021), we get a palindrome (131424303424131).

The spelling of 120421201300110 in words is "one hundred twenty trillion, four hundred twenty-one billion, two hundred one million, three hundred thousand, one hundred ten".

Divisors: 1 2 3 5 6 9 10 15 18 30 45 90 1338013347779 2676026695558 4014040043337 6690066738895 8028080086674 12042120130011 13380133477790 20070200216685 24084240260022 40140400433370 60210600650055 120421201300110