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121021012000181 is a prime number
BaseRepresentation
bin11011100001000101100110…
…011011100011110110110101
3120212111111101101222122221102
4123201011212123203312311
5111330302013033001211
61105220141351255445
734330323332041016
oct3341054633436665
9525444341878842
10121021012000181
11356197a5298907
12116a682407a585
13526b30394c3c7
1421c563bd5100d
15ded07a8d9a3b
hex6e11666e3db5

121021012000181 has 2 divisors, whose sum is σ = 121021012000182. Its totient is φ = 121021012000180.

The previous prime is 121021012000043. The next prime is 121021012000183. The reversal of 121021012000181 is 181000210120121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113403224319025 + 7617787681156 = 10649095^2 + 2760034^2 .

It is a cyclic number.

It is not a de Polignac number, because 121021012000181 - 210 = 121021011999157 is a prime.

It is a super-2 number, since 2×1210210120001812 (a number of 29 digits) contains 22 as substring.

Together with 121021012000183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121021012000183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510506000090 + 60510506000091.

It is an arithmetic number, because the mean of its divisors is an integer number (60510506000091).

Almost surely, 2121021012000181 is an apocalyptic number.

It is an amenable number.

121021012000181 is a deficient number, since it is larger than the sum of its proper divisors (1).

121021012000181 is an equidigital number, since it uses as much as digits as its factorization.

121021012000181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 20.

The spelling of 121021012000181 in words is "one hundred twenty-one trillion, twenty-one billion, twelve million, one hundred eighty-one", and thus it is an aban number.