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1211220211007 is a prime number
BaseRepresentation
bin10001101000000010010…
…110011011010100111111
311021210101000111212221002
4101220002112123110333
5124321034333223012
62324232112400515
7153336110631332
oct21500226332477
94253330455832
101211220211007
11427748261754
121768ab24613b
138a2aa024b11
14428a275c619
152178ec777c2
hex11a0259b53f

1211220211007 has 2 divisors, whose sum is σ = 1211220211008. Its totient is φ = 1211220211006.

The previous prime is 1211220210973. The next prime is 1211220211009. The reversal of 1211220211007 is 7001120221121.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1211220211007 is a prime.

It is a super-4 number, since 4×12112202110074 (a number of 49 digits) contains 4444 as substring.

Together with 1211220211009, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1211220211007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211220211009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605610105503 + 605610105504.

It is an arithmetic number, because the mean of its divisors is an integer number (605610105504).

Almost surely, 21211220211007 is an apocalyptic number.

1211220211007 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211220211007 is an equidigital number, since it uses as much as digits as its factorization.

1211220211007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 20.

Adding to 1211220211007 its reverse (7001120221121), we get a palindrome (8212340432128).

The spelling of 1211220211007 in words is "one trillion, two hundred eleven billion, two hundred twenty million, two hundred eleven thousand, seven".