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1212691356047 is a prime number
BaseRepresentation
bin10001101001011010000…
…010011001100110001111
311021221011112201210112102
4101221122002121212033
5124332042441343142
62325034104225315
7153420423310043
oct21513202314617
94257145653472
101212691356047
114283327237a6
1217703ba6b23b
138a482a53342
14429a1cb0023
1521828ec2532
hex11a5a09998f

1212691356047 has 2 divisors, whose sum is σ = 1212691356048. Its totient is φ = 1212691356046.

The previous prime is 1212691355977. The next prime is 1212691356049. The reversal of 1212691356047 is 7406531962121.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1212691356047 - 216 = 1212691290511 is a prime.

It is a super-2 number, since 2×12126913560472 (a number of 25 digits) contains 22 as substring.

Together with 1212691356049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1212691355992 and 1212691356010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1212691356049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606345678023 + 606345678024.

It is an arithmetic number, because the mean of its divisors is an integer number (606345678024).

Almost surely, 21212691356047 is an apocalyptic number.

1212691356047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212691356047 is an equidigital number, since it uses as much as digits as its factorization.

1212691356047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 47.

The spelling of 1212691356047 in words is "one trillion, two hundred twelve billion, six hundred ninety-one million, three hundred fifty-six thousand, forty-seven".