Base | Representation |
---|---|
bin | 1011000010000111111010… |
… | …1000001111000000000000 |
3 | 1120221201112001122220200202 |
4 | 2300201332220033000000 |
5 | 3042224004200322240 |
6 | 41444542253504332 |
7 | 2361305160443114 |
oct | 260417650170000 |
9 | 46851461586622 |
10 | 12131112120320 |
11 | 3957859597436 |
12 | 143b110aa20a8 |
13 | 69cc60ac9a7b |
14 | 2dd212a5d744 |
15 | 160858711315 |
hex | b087ea0f000 |
12131112120320 has 104 divisors (see below), whose sum is σ = 30643279985040. Its totient is φ = 4597052866560.
The previous prime is 12131112120311. The next prime is 12131112120331. The reversal of 12131112120320 is 2302121113121.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 12131112120292 and 12131112120301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15198761 + ... + 15977000.
Almost surely, 212131112120320 is an apocalyptic number.
12131112120320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12131112120320 is an abundant number, since it is smaller than the sum of its proper divisors (18512167864720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12131112120320 is an equidigital number, since it uses as much as digits as its factorization.
12131112120320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31175809 (or 31175787 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 12131112120320 its reverse (2302121113121), we get a palindrome (14433233233441).
The spelling of 12131112120320 in words is "twelve trillion, one hundred thirty-one billion, one hundred twelve million, one hundred twenty thousand, three hundred twenty".
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