Base | Representation |
---|---|
bin | 1011000010001111011110… |
… | …0010000000101100100000 |
3 | 1120221220202102110220102021 |
4 | 2300203313202000230200 |
5 | 3042242132434011000 |
6 | 41445515433431224 |
7 | 2361406350606565 |
oct | 260436742005440 |
9 | 46856672426367 |
10 | 12133140532000 |
11 | 39586aa57a124 |
12 | 143b59826b514 |
13 | 6a01c5111177 |
14 | 2dd3661d286c |
15 | 16092683711a |
hex | b08f7880b20 |
12133140532000 has 96 divisors (see below), whose sum is σ = 29977670661120. Its totient is φ = 4826142764800.
The previous prime is 12133140531949. The next prime is 12133140532001. The reversal of 12133140532000 is 23504133121.
It is a happy number.
It is a super-2 number, since 2×121331405320002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (12133140532001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7756864 + ... + 9188863.
It is an arithmetic number, because the mean of its divisors is an integer number (312267402720).
Almost surely, 212133140532000 is an apocalyptic number.
12133140532000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12133140532000 is an abundant number, since it is smaller than the sum of its proper divisors (17844530129120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12133140532000 is a wasteful number, since it uses less digits than its factorization.
12133140532000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16945931 (or 16945913 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 12133140532000 its reverse (23504133121), we get a palindrome (12156644665121).
The spelling of 12133140532000 in words is "twelve trillion, one hundred thirty-three billion, one hundred forty million, five hundred thirty-two thousand".
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