Base | Representation |
---|---|
bin | 1011000010110101101111… |
… | …0010001100100101100000 |
3 | 1120222220021021212110010101 |
4 | 2300231123302030211200 |
5 | 3042424202040244300 |
6 | 41454335012112144 |
7 | 2362222036402561 |
oct | 260553362144540 |
9 | 46886237773111 |
10 | 12143412431200 |
11 | 3961aa0815016 |
12 | 1441584305654 |
13 | 6a117123aa2b |
14 | 2dda5c4d2168 |
15 | 160d28502b6a |
hex | b0b5bc8c960 |
12143412431200 has 72 divisors (see below), whose sum is σ = 29645620183872. Its totient is φ = 4857280657920.
The previous prime is 12143412431177. The next prime is 12143412431203. The reversal of 12143412431200 is 213421434121.
It is a happy number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12143412431203) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 67980402 + ... + 68158798.
It is an arithmetic number, because the mean of its divisors is an integer number (411744724776).
Almost surely, 212143412431200 is an apocalyptic number.
12143412431200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12143412431200 is an abundant number, since it is smaller than the sum of its proper divisors (17502207752672).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12143412431200 is a wasteful number, since it uses less digits than its factorization.
12143412431200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 263504 (or 263491 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 12143412431200 its reverse (213421434121), we get a palindrome (12356833865321).
The spelling of 12143412431200 in words is "twelve trillion, one hundred forty-three billion, four hundred twelve million, four hundred thirty-one thousand, two hundred".
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