Base | Representation |
---|---|
bin | 10001101011101010010… |
… | …110100010011000101110 |
3 | 11022011102021122101202210 |
4 | 101223222112202120232 |
5 | 124402022303212110 |
6 | 2330114235031250 |
7 | 153534423202224 |
oct | 21535226423056 |
9 | 4264367571683 |
10 | 1215112554030 |
11 | 4293653a4671 |
12 | 1775b689b526 |
13 | 8a77a55177b |
14 | 42b5168ab14 |
15 | 2191b834520 |
hex | 11aea5a262e |
1215112554030 has 64 divisors (see below), whose sum is σ = 3081584424960. Its totient is φ = 306018425856.
The previous prime is 1215112553983. The next prime is 1215112554041. The reversal of 1215112554030 is 304552115121.
It is a super-2 number, since 2×12151125540302 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11091267 + ... + 11200286.
It is an arithmetic number, because the mean of its divisors is an integer number (48149756640).
Almost surely, 21215112554030 is an apocalyptic number.
1215112554030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1215112554030 is an abundant number, since it is smaller than the sum of its proper divisors (1866471870930).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1215112554030 is a wasteful number, since it uses less digits than its factorization.
1215112554030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22291665.
The product of its (nonzero) digits is 6000, while the sum is 30.
Adding to 1215112554030 its reverse (304552115121), we get a palindrome (1519664669151).
The spelling of 1215112554030 in words is "one trillion, two hundred fifteen billion, one hundred twelve million, five hundred fifty-four thousand, thirty".
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