Base | Representation |
---|---|
bin | 1011001000011110110101… |
… | …0011011010001000111100 |
3 | 1121100011110120001100010101 |
4 | 2302013231103122020330 |
5 | 3101021210314124200 |
6 | 42011045213050444 |
7 | 2402223053535400 |
oct | 262075523321074 |
9 | 47304416040111 |
10 | 12240343114300 |
11 | 399a111645984 |
12 | 1458316186a24 |
13 | 6aa34aba6312 |
14 | 304615a65100 |
15 | 1635ed05526a |
hex | b21ed4da23c |
12240343114300 has 108 divisors (see below), whose sum is σ = 30954616553784. Its totient is φ = 4189015958400.
The previous prime is 12240343114273. The next prime is 12240343114301. The reversal of 12240343114300 is 341134304221.
It is a happy number.
12240343114300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (28).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12240343114301) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 396910 + ... + 4963690.
Almost surely, 212240343114300 is an apocalyptic number.
12240343114300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12240343114300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15477308276892).
12240343114300 is an abundant number, since it is smaller than the sum of its proper divisors (18714273439484).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12240343114300 is a wasteful number, since it uses less digits than its factorization.
12240343114300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4567356 (or 4567342 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 12240343114300 its reverse (341134304221), we get a palindrome (12581477418521).
It can be divided in two parts, 1224034 and 3114300, that added together give a palindrome (4338334).
The spelling of 12240343114300 in words is "twelve trillion, two hundred forty billion, three hundred forty-three million, one hundred fourteen thousand, three hundred".
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