123102135004125 has 32 divisors (see below), whose sum is σ = 205089048403200. Its totient is φ = 65575274644800.

The previous prime is 123102135004097. The next prime is 123102135004127. The reversal of 123102135004125 is 521400531201321.

It is a happy number.

It is not a de Polignac number, because 123102135004125 - 2¹⁸ = 123102134741981 is a prime.

It is a super-2 number, since 2×123102135004125² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 123102135004092 and 123102135004101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123102135004127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 197682105 + ... + 198303854.

It is an arithmetic number, because the mean of its divisors is an integer number (6409032762600).

Almost surely, 2^{123102135004125} is an apocalyptic number.

123102135004125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

123102135004125 is a deficient number, since it is larger than the sum of its proper divisors (81986913399075).

123102135004125 is an equidigital number, since it uses as much as digits as its factorization.

123102135004125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 395986806 (or 395986796 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 30.

Adding to 123102135004125 its reverse (521400531201321), we get a palindrome (644502666205446).

The spelling of 123102135004125 in words is "one hundred twenty-three trillion, one hundred two billion, one hundred thirty-five million, four thousand, one hundred twenty-five".