Base | Representation |
---|---|
bin | 1011001101110001010100… |
… | …0100000110100111110010 |
3 | 1121122211222211210011211210 |
4 | 2303130111010012213302 |
5 | 3104013301323112200 |
6 | 42120513244020550 |
7 | 2411620512601335 |
oct | 263342504064762 |
9 | 47584884704753 |
10 | 12331204504050 |
11 | 3a246a8517923 |
12 | 1471a53531756 |
13 | 6b5a9b2c3b73 |
14 | 308b9510c61c |
15 | 165b69d33650 |
hex | b37151069f2 |
12331204504050 has 96 divisors (see below), whose sum is σ = 30705170011200. Its totient is φ = 3275022643200.
The previous prime is 12331204504009. The next prime is 12331204504063. The reversal of 12331204504050 is 5040540213321.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 12331204503999 and 12331204504017.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 87728226 + ... + 87868674.
It is an arithmetic number, because the mean of its divisors is an integer number (319845520950).
Almost surely, 212331204504050 is an apocalyptic number.
12331204504050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 12331204504050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15352585005600).
12331204504050 is an abundant number, since it is smaller than the sum of its proper divisors (18373965507150).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12331204504050 is a wasteful number, since it uses less digits than its factorization.
12331204504050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 142828 (or 142823 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 12331204504050 its reverse (5040540213321), we get a palindrome (17371744717371).
The spelling of 12331204504050 in words is "twelve trillion, three hundred thirty-one billion, two hundred four million, five hundred four thousand, fifty".
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