Base | Representation |
---|---|
bin | 111001011010111111… |
… | …0011000011010010100 |
3 | 102210021211111101210102 |
4 | 1302311332120122110 |
5 | 4010020400111200 |
6 | 132352050313232 |
7 | 11623534445255 |
oct | 1626576303224 |
9 | 383254441712 |
10 | 123312113300 |
11 | 48329522942 |
12 | 1ba94b88818 |
13 | b82244b11c |
14 | 5d7b196b2c |
15 | 331ab4c6d5 |
hex | 1cb5f98694 |
123312113300 has 72 divisors (see below), whose sum is σ = 271119298296. Its totient is φ = 48676700160.
The previous prime is 123312113251. The next prime is 123312113347. The reversal of 123312113300 is 3311213321.
It can be written as a sum of positive squares in 12 ways, for example, as 43758782596 + 79553330704 = 209186^2 + 282052^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3406094 + ... + 3442106.
Almost surely, 2123312113300 is an apocalyptic number.
123312113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 123312113300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (135559649148).
123312113300 is an abundant number, since it is smaller than the sum of its proper divisors (147807184996).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123312113300 is a wasteful number, since it uses less digits than its factorization.
123312113300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36477 (or 36470 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 123312113300 its reverse (3311213321), we get a palindrome (126623326621).
It can be divided in two parts, 1233121 and 13300, that added together give a palindrome (1246421).
The spelling of 123312113300 in words is "one hundred twenty-three billion, three hundred twelve million, one hundred thirteen thousand, three hundred".
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