124011314040 has 32 divisors (see below), whose sum is σ = 372033942480. Its totient is φ = 33069683712.

The previous prime is 124011314029. The next prime is 124011314047. The reversal of 124011314040 is 40413110421.

It is a super-2 number, since 2×124011314040² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 124011313998 and 124011314016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (124011314047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 516713689 + ... + 516713928.

Almost surely, 2^124011314040 is an apocalyptic number.

124011314040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

124011314040 is an abundant number, since it is smaller than the sum of its proper divisors (248022628440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

124011314040 is a wasteful number, since it uses less digits than its factorization.

124011314040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1033427631 (or 1033427627 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 124011314040 its reverse (40413110421), we get a palindrome (164424424461).

The spelling of 124011314040 in words is "one hundred twenty-four billion, eleven million, three hundred fourteen thousand, forty".