Base | Representation |
---|---|
bin | 11100011101000101001111… |
… | …001101110110000100010110 |
3 | 121102002121222222021112211022 |
4 | 130131011033031312010112 |
5 | 112400323441012223300 |
6 | 1122054133004241142 |
7 | 35234224543334342 |
oct | 3435051715660426 |
9 | 542077888245738 |
10 | 125143791132950 |
11 | 3696920266a137 |
12 | 120518565401b2 |
13 | 54aa016634355 |
14 | 22c8dc5748622 |
15 | e70425812285 |
hex | 71d14f376116 |
125143791132950 has 24 divisors (see below), whose sum is σ = 233501733718272. Its totient is φ = 49899606300320.
The previous prime is 125143791132947. The next prime is 125143791132959. The reversal of 125143791132950 is 59231197341521.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 125143791132892 and 125143791132901.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (125143791132959) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3947737814 + ... + 3947769513.
It is an arithmetic number, because the mean of its divisors is an integer number (9729238904928).
Almost surely, 2125143791132950 is an apocalyptic number.
125143791132950 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
125143791132950 is a deficient number, since it is larger than the sum of its proper divisors (108357942585322).
125143791132950 is a wasteful number, since it uses less digits than its factorization.
125143791132950 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7895507656 (or 7895507651 counting only the distinct ones).
The product of its (nonzero) digits is 2041200, while the sum is 53.
The spelling of 125143791132950 in words is "one hundred twenty-five trillion, one hundred forty-three billion, seven hundred ninety-one million, one hundred thirty-two thousand, nine hundred fifty".
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