Base | Representation |
---|---|
bin | 11101000111011110110011… |
… | …001000010011111010111010 |
3 | 121210102011200020022120021022 |
4 | 131013132303020103322322 |
5 | 113241043132014340100 |
6 | 1132204441025542442 |
7 | 35654563055461451 |
oct | 3507366310237272 |
9 | 553364606276238 |
10 | 128057455230650 |
11 | 37891953032640 |
12 | 124424867a4a22 |
13 | 565b9c64a521a |
14 | 238a02a219b98 |
15 | ec11056ece85 |
hex | 7477b3213eba |
128057455230650 has 96 divisors (see below), whose sum is σ = 263731165607232. Its totient is φ = 45869112115200.
The previous prime is 128057455230577. The next prime is 128057455230667. The reversal of 128057455230650 is 56032554750821.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 128057455230592 and 128057455230601.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 891587642 + ... + 891731258.
It is an arithmetic number, because the mean of its divisors is an integer number (2747199641742).
Almost surely, 2128057455230650 is an apocalyptic number.
128057455230650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
128057455230650 is an abundant number, since it is smaller than the sum of its proper divisors (135673710376582).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
128057455230650 is a wasteful number, since it uses less digits than its factorization.
128057455230650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 167904 (or 167899 counting only the distinct ones).
The product of its (nonzero) digits is 10080000, while the sum is 53.
The spelling of 128057455230650 in words is "one hundred twenty-eight trillion, fifty-seven billion, four hundred fifty-five million, two hundred thirty thousand, six hundred fifty".
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