1300011313200 has 120 divisors (see below), whose sum is σ = 4164753708048. Its totient is φ = 346637706240.

The previous prime is 1300011313199. The next prime is 1300011313219. The reversal of 1300011313200 is 23131100031.

It is a tau number, because it is divible by the number of its divisors (120).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1300011313200.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14803822 + ... + 14891378.

Almost surely, 2^{1300011313200} is an apocalyptic number.

1300011313200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1300011313200 is an abundant number, since it is smaller than the sum of its proper divisors (2864742394848).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300011313200 is a wasteful number, since it uses less digits than its factorization.

1300011313200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99951 (or 99940 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1300011313200 its reverse (23131100031), we get a palindrome (1323142413231).

The spelling of 1300011313200 in words is "one trillion, three hundred billion, eleven million, three hundred thirteen thousand, two hundred".