130001333120 has 64 divisors (see below), whose sum is σ = 311116148640. Its totient is φ = 51945031680.

The previous prime is 130001333101. The next prime is 130001333123. The reversal of 130001333120 is 21333100031.

It is a tau number, because it is divible by the number of its divisors (64).

It is a super-2 number, since 2×130001333120² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130001333123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 494309 + ... + 710171.

Almost surely, 2^130001333120 is an apocalyptic number.

130001333120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130001333120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (155558074320).

130001333120 is an abundant number, since it is smaller than the sum of its proper divisors (181114815520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130001333120 is an equidigital number, since it uses as much as digits as its factorization.

130001333120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 216823 (or 216811 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 130001333120 its reverse (21333100031), we get a palindrome (151334433151).

The spelling of 130001333120 in words is "one hundred thirty billion, one million, three hundred thirty-three thousand, one hundred twenty".