Base | Representation |
---|---|
bin | 10010111010110100000… |
… | …100000111110111111100 |
3 | 11121021210021121000121102 |
4 | 102322310010013313330 |
5 | 132300101340244400 |
6 | 2433131434352232 |
7 | 162633501016532 |
oct | 22726404076774 |
9 | 4537707530542 |
10 | 1300101103100 |
11 | 4614081a7478 |
12 | 18bb7528b678 |
13 | 957a3036067 |
14 | 46cd4b86152 |
15 | 23c42c469d5 |
hex | 12eb4107dfc |
1300101103100 has 72 divisors (see below), whose sum is σ = 2825453534400. Its totient is φ = 519260600320.
The previous prime is 1300101103099. The next prime is 1300101103111. The reversal of 1300101103100 is 13011010031.
It is a happy number.
It is a super-2 number, since 2×13001011031002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 321089876 + ... + 321093924.
It is an arithmetic number, because the mean of its divisors is an integer number (39242410200).
Almost surely, 21300101103100 is an apocalyptic number.
1300101103100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1300101103100 is an abundant number, since it is smaller than the sum of its proper divisors (1525352431300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300101103100 is a wasteful number, since it uses less digits than its factorization.
1300101103100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8087 (or 8080 counting only the distinct ones).
The product of its (nonzero) digits is 9, while the sum is 11.
Adding to 1300101103100 its reverse (13011010031), we get a palindrome (1313112113131).
The spelling of 1300101103100 in words is "one trillion, three hundred billion, one hundred one million, one hundred three thousand, one hundred".
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