Base | Representation |
---|---|
bin | 11101100011111001011100… |
… | …111110110100110011100010 |
3 | 122001022212002202210020201120 |
4 | 131203321130332310303202 |
5 | 114020041412311214020 |
6 | 1140301512012313110 |
7 | 36245633310364065 |
oct | 3543713476646342 |
9 | 561285082706646 |
10 | 130010220023010 |
11 | 3847502a930838 |
12 | 126b8a27772796 |
13 | 5770baca1a692 |
14 | 24167576368dc |
15 | 1006ce6918740 |
hex | 763e5cfb4ce2 |
130010220023010 has 64 divisors (see below), whose sum is σ = 326792254464000. Its totient is φ = 33039657984960.
The previous prime is 130010220022997. The next prime is 130010220023017. The reversal of 130010220023010 is 10320022010031.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is not an unprimeable number, because it can be changed into a prime (130010220023017) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 347452510 + ... + 347826489.
It is an arithmetic number, because the mean of its divisors is an integer number (5106128976000).
Almost surely, 2130010220023010 is an apocalyptic number.
130010220023010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130010220023010 is an abundant number, since it is smaller than the sum of its proper divisors (196782034440990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130010220023010 is a wasteful number, since it uses less digits than its factorization.
130010220023010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 695279303.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 130010220023010 its reverse (10320022010031), we get a palindrome (140330242033041).
The spelling of 130010220023010 in words is "one hundred thirty trillion, ten billion, two hundred twenty million, twenty-three thousand, ten".
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