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130011103422 = 232173137370421
BaseRepresentation
bin111100100010101000…
…1000000000010111110
3110102120200211100122200
41321011101000002332
54112230320302142
6135420513052330
712251540100564
oct1710521000276
9412520740580
10130011103422
1150156973312
12212445570a6
13c34c2916c5
146414b59a34
1535add0864c
hex1e454400be

130011103422 has 96 divisors (see below), whose sum is σ = 316204072704. Its totient is φ = 38405145600.

The previous prime is 130011103421. The next prime is 130011103429. The reversal of 130011103422 is 224301110031.

130011103422 is a `hidden beast` number, since 1 + 300 + 11 + 10 + 342 + 2 = 666.

It is a super-2 number, since 2×1300111034222 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 130011103395 and 130011103404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130011103421) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 165772 + ... + 536192.

It is an arithmetic number, because the mean of its divisors is an integer number (3293792424).

Almost surely, 2130011103422 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130011103422, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (158102036352).

130011103422 is an abundant number, since it is smaller than the sum of its proper divisors (186192969282).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130011103422 is a wasteful number, since it uses less digits than its factorization.

130011103422 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 370514 (or 370511 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 130011103422 its reverse (224301110031), we get a palindrome (354312213453).

The spelling of 130011103422 in words is "one hundred thirty billion, eleven million, one hundred three thousand, four hundred twenty-two".

Divisors: 1 2 3 6 9 17 18 31 34 37 51 62 74 93 102 111 153 186 222 279 306 333 527 558 629 666 1054 1147 1258 1581 1887 2294 3162 3441 3774 4743 5661 6882 9486 10323 11322 19499 20646 38998 58497 116994 175491 350982 370421 740842 1111263 2222526 3333789 6297157 6667578 11483051 12594314 13705577 18891471 22966102 27411154 34449153 37782942 41116731 56674413 68898306 82233462 103347459 113348826 123350193 195211867 206694918 232994809 246700386 390423734 424872887 465989618 585635601 698984427 849745774 1171271202 1274618661 1397968854 1756906803 2096953281 2549237322 3513813606 3823855983 4193906562 7222839079 7647711966 14445678158 21668517237 43337034474 65005551711 130011103422