Base | Representation |
---|---|
bin | 11101100011111100011011… |
… | …001011110111000101001010 |
3 | 122001100011100011101022211121 |
4 | 131203330123023313011022 |
5 | 114020114431221024432 |
6 | 1140303200404345454 |
7 | 36246105346236241 |
oct | 3543743313670512 |
9 | 561304304338747 |
10 | 130013411111242 |
11 | 3847641814763a |
12 | 126b95783a528a |
13 | 577129ab88a79 |
14 | 241697b381958 |
15 | 1006e31b56197 |
hex | 763f1b2f714a |
130013411111242 has 64 divisors (see below), whose sum is σ = 221513089461120. Its totient is φ = 56855627771904.
The previous prime is 130013411111239. The next prime is 130013411111273. The reversal of 130013411111242 is 242111114310031.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 145854633 + ... + 146743315.
It is an arithmetic number, because the mean of its divisors is an integer number (3461142022830).
Almost surely, 2130013411111242 is an apocalyptic number.
130013411111242 is a deficient number, since it is larger than the sum of its proper divisors (91499678349878).
130013411111242 is a wasteful number, since it uses less digits than its factorization.
130013411111242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 893047.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 130013411111242 its reverse (242111114310031), we get a palindrome (372124525421273).
The spelling of 130013411111242 in words is "one hundred thirty trillion, thirteen billion, four hundred eleven million, one hundred eleven thousand, two hundred forty-two".
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