Base | Representation |
---|---|
bin | 111100100010101110… |
… | …0001101000001001110 |
3 | 110102120220100120002002 |
4 | 1321011130031001032 |
5 | 4112232043241032 |
6 | 135421100032302 |
7 | 12251604051500 |
oct | 1710534150116 |
9 | 412526316062 |
10 | 130014040142 |
11 | 50158599758 |
12 | 21245532692 |
13 | c34ca7c2cc |
14 | 64152c1d70 |
15 | 35ae1d8862 |
hex | 1e4570d04e |
130014040142 has 96 divisors (see below), whose sum is σ = 249705089280. Its totient is φ = 50386976640.
The previous prime is 130014040133. The next prime is 130014040181. The reversal of 130014040142 is 241040410031.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 22309433 + ... + 22315259.
It is an arithmetic number, because the mean of its divisors is an integer number (2601094680).
Almost surely, 2130014040142 is an apocalyptic number.
130014040142 is a deficient number, since it is larger than the sum of its proper divisors (119691049138).
130014040142 is a wasteful number, since it uses less digits than its factorization.
130014040142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6406 (or 6399 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 130014040142 its reverse (241040410031), we get a palindrome (371054450173).
The spelling of 130014040142 in words is "one hundred thirty billion, fourteen million, forty thousand, one hundred forty-two".
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