1300243435000 has 160 divisors (see below), whose sum is σ = 3267329432400. Its totient is φ = 483425280000.

The previous prime is 1300243434961. The next prime is 1300243435009. The reversal of 1300243435000 is 5343420031.

It is a super-3 number, since 3×1300243435000³ (a number of 37 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300243435009) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 4905880 + ... + 5164120.

Almost surely, 2^{1300243435000} is an apocalyptic number.

1300243435000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300243435000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1633664716200).

1300243435000 is an abundant number, since it is smaller than the sum of its proper divisors (1967085997400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300243435000 is a wasteful number, since it uses less digits than its factorization.

1300243435000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 258339 (or 258320 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 1300243435000 its reverse (5343420031), we get a palindrome (1305586855031).

The spelling of 1300243435000 in words is "one trillion, three hundred billion, two hundred forty-three million, four hundred thirty-five thousand".