Base | Representation |
---|---|
bin | 111100100011100000… |
… | …1010011011011110000 |
3 | 110102122202020001002221 |
4 | 1321013001103123300 |
5 | 4112310334333320 |
6 | 135423444050424 |
7 | 12252345243256 |
oct | 1710701233360 |
9 | 412582201087 |
10 | 130040542960 |
11 | 50171550709 |
12 | 21252393a14 |
13 | c3553cb553 |
14 | 6418a205d6 |
15 | 35b16c13aa |
hex | 1e470536f0 |
130040542960 has 40 divisors (see below), whose sum is σ = 309718520496. Its totient is φ = 50747527680.
The previous prime is 130040542943. The next prime is 130040542967. The reversal of 130040542960 is 69245040031.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (40).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130040542967) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19819974 + ... + 19826533.
Almost surely, 2130040542960 is an apocalyptic number.
130040542960 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130040542960 is an abundant number, since it is smaller than the sum of its proper divisors (179677977536).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130040542960 is a wasteful number, since it uses less digits than its factorization.
130040542960 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39646561 (or 39646555 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 34.
Adding to 130040542960 its reverse (69245040031), we get a palindrome (199285582991).
The spelling of 130040542960 in words is "one hundred thirty billion, forty million, five hundred forty-two thousand, nine hundred sixty".
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