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13004421400 = 2352972272953
BaseRepresentation
bin11000001110001111…
…11011100100011000
31020120022010001111001
430013013323210120
5203113112441100
65550225514344
7640155521005
oct140707734430
936508101431
1013004421400
115573725303
12262b1a29b4
1312c328c309
148b519a8ac
15511a26d6a
hex3071fb918

13004421400 has 96 divisors (see below), whose sum is σ = 30691941840. Its totient is φ = 5123727360.

The previous prime is 13004421359. The next prime is 13004421403. The reversal of 13004421400 is 412440031.

13004421400 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×130044214002 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13004421403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4402324 + ... + 4405276.

Almost surely, 213004421400 is an apocalyptic number.

13004421400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13004421400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15345970920).

13004421400 is an abundant number, since it is smaller than the sum of its proper divisors (17687520440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004421400 is a wasteful number, since it uses less digits than its factorization.

13004421400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3293 (or 3284 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 13004421400 its reverse (412440031), we get a palindrome (13416861431).

The spelling of 13004421400 in words is "thirteen billion, four million, four hundred twenty-one thousand, four hundred".

Divisors: 1 2 4 5 8 10 20 25 40 50 97 100 194 200 227 388 454 485 776 908 970 1135 1816 1940 2270 2425 2953 3880 4540 4850 5675 5906 9080 9700 11350 11812 14765 19400 22019 22700 23624 29530 44038 45400 59060 73825 88076 110095 118120 147650 176152 220190 286441 295300 440380 550475 572882 590600 670331 880760 1100950 1145764 1340662 1432205 2201900 2291528 2681324 2864410 3351655 4403800 5362648 5728820 6703310 7161025 11457640 13406620 14322050 16758275 26813240 28644100 33516550 57288200 65022107 67033100 130044214 134066200 260088428 325110535 520176856 650221070 1300442140 1625552675 2600884280 3251105350 6502210700 13004421400