Base | Representation |
---|---|
bin | 111100100011101001… |
… | …0110110100001001000 |
3 | 110102200001212202022221 |
4 | 1321013102312201020 |
5 | 4112313024034422 |
6 | 135424130423424 |
7 | 12252432322633 |
oct | 1710722664110 |
9 | 412601782287 |
10 | 130045143112 |
11 | 50174102895 |
12 | 21253a31b74 |
13 | c35634c331 |
14 | 641949ac1a |
15 | 35b1cce3c7 |
hex | 1e474b6848 |
130045143112 has 32 divisors (see below), whose sum is σ = 252032529600. Its totient is φ = 62872603200.
The previous prime is 130045143001. The next prime is 130045143139. The reversal of 130045143112 is 211341540031.
It is a super-2 number, since 2×1300451431122 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2229564 + ... + 2287147.
It is an arithmetic number, because the mean of its divisors is an integer number (7876016550).
Almost surely, 2130045143112 is an apocalyptic number.
It is an amenable number.
130045143112 is a deficient number, since it is larger than the sum of its proper divisors (121987386488).
130045143112 is a wasteful number, since it uses less digits than its factorization.
130045143112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4516837 (or 4516833 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 130045143112 its reverse (211341540031), we get a palindrome (341386683143).
The spelling of 130045143112 in words is "one hundred thirty billion, forty-five million, one hundred forty-three thousand, one hundred twelve".
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