Base | Representation |
---|---|
bin | 1011110101000011111111… |
… | …1101110100000101111010 |
3 | 1201001101100211010201002110 |
4 | 2331100333331310011322 |
5 | 3201043231420003200 |
6 | 43354551555513150 |
7 | 2511445415050623 |
oct | 275207775640572 |
9 | 51041324121073 |
10 | 13006234141050 |
11 | 4164a05112187 |
12 | 15608415b87b6 |
13 | 734637403287 |
14 | 32d70dd82a4a |
15 | 1784c6b1eb50 |
hex | bd43ff7417a |
13006234141050 has 96 divisors (see below), whose sum is σ = 34269548572800. Its totient is φ = 3258225250560.
The previous prime is 13006234141007. The next prime is 13006234141067. The reversal of 13006234141050 is 5014143260031.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 13006234140999 and 13006234141017.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 40243630 + ... + 40565529.
It is an arithmetic number, because the mean of its divisors is an integer number (356974464300).
Almost surely, 213006234141050 is an apocalyptic number.
13006234141050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13006234141050 is an abundant number, since it is smaller than the sum of its proper divisors (21263314431750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13006234141050 is a wasteful number, since it uses less digits than its factorization.
13006234141050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80809240 (or 80809235 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 30.
The spelling of 13006234141050 in words is "thirteen trillion, six billion, two hundred thirty-four million, one hundred forty-one thousand, fifty".
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