Base | Representation |
---|---|
bin | 1011110101010101110000… |
… | …1011010111011011111010 |
3 | 1201001211200010111112021220 |
4 | 2331111130023113123322 |
5 | 3201133013110014114 |
6 | 43401101052412510 |
7 | 2512004524555440 |
oct | 275253413273372 |
9 | 51054603445256 |
10 | 13011002423034 |
11 | 4166a31742aa0 |
12 | 1561752477136 |
13 | 734c172508c5 |
14 | 32da43366b90 |
15 | 1786a55540a9 |
hex | bd55c2d76fa |
13011002423034 has 64 divisors (see below), whose sum is σ = 32899963041792. Its totient is φ = 3331882814400.
The previous prime is 13011002423017. The next prime is 13011002423119. The reversal of 13011002423034 is 43032420011031.
It is a happy number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13011002422995 and 13011002423013.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 198293557 + ... + 198359160.
It is an arithmetic number, because the mean of its divisors is an integer number (514061922528).
Almost surely, 213011002423034 is an apocalyptic number.
13011002423034 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13011002423034 is an abundant number, since it is smaller than the sum of its proper divisors (19888960618758).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13011002423034 is a wasteful number, since it uses less digits than its factorization.
13011002423034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 396652811.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13011002423034 its reverse (43032420011031), we get a palindrome (56043422434065).
The spelling of 13011002423034 in words is "thirteen trillion, eleven billion, two million, four hundred twenty-three thousand, thirty-four".
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