1301454425111 has 2 divisors, whose sum is σ = 1301454425112. Its totient is φ = 1301454425110.

The previous prime is 1301454425083. The next prime is 1301454425143. The reversal of 1301454425111 is 1115244541031.

It is an a-pointer prime, because the next prime (1301454425143) can be obtained adding 1301454425111 to its sum of digits (32).

It is a weak prime.

It is an emirp because it is prime and its reverse (1115244541031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1301454425111 - 2²² = 1301450230807 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301454425191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650727212555 + 650727212556.

It is an arithmetic number, because the mean of its divisors is an integer number (650727212556).

Almost surely, 2^{1301454425111} is an apocalyptic number.

1301454425111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301454425111 is an equidigital number, since it uses as much as digits as its factorization.

1301454425111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9600, while the sum is 32.

Adding to 1301454425111 its reverse (1115244541031), we get a palindrome (2416698966142).

The spelling of 1301454425111 in words is "one trillion, three hundred one billion, four hundred fifty-four million, four hundred twenty-five thousand, one hundred eleven".