Base | Representation |
---|---|
bin | 11101100111001001000010… |
… | …111110011011111101001000 |
3 | 122002010011110012012120100110 |
4 | 131213021002332123331020 |
5 | 114032214413213404000 |
6 | 1140552134215434320 |
7 | 36301014112134156 |
oct | 3547110276337510 |
9 | 562104405176313 |
10 | 130233122013000 |
11 | 38550614229a96 |
12 | 127340750859a0 |
13 | 5788c13a00c06 |
14 | 24234611b23d6 |
15 | 100c9e078c850 |
hex | 767242f9bf48 |
130233122013000 has 64 divisors (see below), whose sum is σ = 406327340689920. Its totient is φ = 34728832536000.
The previous prime is 130233122012963. The next prime is 130233122013011. The reversal of 130233122013000 is 310221332031.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21705517336 + ... + 21705523335.
It is an arithmetic number, because the mean of its divisors is an integer number (6348864698280).
Almost surely, 2130233122013000 is an apocalyptic number.
130233122013000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130233122013000 is an abundant number, since it is smaller than the sum of its proper divisors (276094218676920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130233122013000 is a wasteful number, since it uses less digits than its factorization.
130233122013000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43411040695 (or 43411040681 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 130233122013000 its reverse (310221332031), we get a palindrome (130543343345031).
The spelling of 130233122013000 in words is "one hundred thirty trillion, two hundred thirty-three billion, one hundred twenty-two million, thirteen thousand".
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