Base | Representation |
---|---|
bin | 11101101000001000100101… |
… | …010110010100100000011000 |
3 | 122002100200112201201122112012 |
4 | 131220020211112110200120 |
5 | 114034324123133343300 |
6 | 1141043340011005052 |
7 | 36305650533141302 |
oct | 3550104526244030 |
9 | 562320481648465 |
10 | 130301344434200 |
11 | 38577542a90875 |
12 | 12745334739788 |
13 | 5792496aa8994 |
14 | 2426893aaa972 |
15 | 100e684cc3435 |
hex | 768225594818 |
130301344434200 has 24 divisors (see below), whose sum is σ = 302950625809980. Its totient is φ = 52120537773600.
The previous prime is 130301344434179. The next prime is 130301344434227. The reversal of 130301344434200 is 2434443103031.
It is a super-3 number, since 3×1303013444342003 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 325753360886 + ... + 325753361285.
Almost surely, 2130301344434200 is an apocalyptic number.
130301344434200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130301344434200 is an abundant number, since it is smaller than the sum of its proper divisors (172649281375780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130301344434200 is a wasteful number, since it uses less digits than its factorization.
130301344434200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 651506722187 (or 651506722178 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 130301344434200 its reverse (2434443103031), we get a palindrome (132735787537231).
The spelling of 130301344434200 in words is "one hundred thirty trillion, three hundred one billion, three hundred forty-four million, four hundred thirty-four thousand, two hundred".
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