Base | Representation |
---|---|
bin | 111100101011111100… |
… | …0001001011110001010 |
3 | 110110101110101102000120 |
4 | 1321113320021132022 |
5 | 4113400234334110 |
6 | 135511505444110 |
7 | 12262351146564 |
oct | 1712770113612 |
9 | 413343342016 |
10 | 130323355530 |
11 | 502a7155a05 |
12 | 21311040636 |
13 | c39bb8c174 |
14 | 64443dc334 |
15 | 35cb437870 |
hex | 1e57e0978a |
130323355530 has 64 divisors (see below), whose sum is σ = 323906204160. Its totient is φ = 33535688256.
The previous prime is 130323355517. The next prime is 130323355531. The reversal of 130323355530 is 35553323031.
It is a junction number, because it is equal to n+sod(n) for n = 130323355491 and 130323355500.
It is not an unprimeable number, because it can be changed into a prime (130323355531) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 501520 + ... + 715659.
It is an arithmetic number, because the mean of its divisors is an integer number (5061034440).
Almost surely, 2130323355530 is an apocalyptic number.
130323355530 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130323355530 is an abundant number, since it is smaller than the sum of its proper divisors (193582848630).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130323355530 is a wasteful number, since it uses less digits than its factorization.
130323355530 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1217315.
The product of its (nonzero) digits is 60750, while the sum is 33.
Adding to 130323355530 its reverse (35553323031), we get a palindrome (165876678561).
The spelling of 130323355530 in words is "one hundred thirty billion, three hundred twenty-three million, three hundred fifty-five thousand, five hundred thirty".
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