Base | Representation |
---|---|
bin | 111100101110101001… |
… | …0111000110000101010 |
3 | 110110121210102101020022 |
4 | 1321131102320300222 |
5 | 4114042022013200 |
6 | 135524514000442 |
7 | 12264533562236 |
oct | 1713522706052 |
9 | 413553371208 |
10 | 130414251050 |
11 | 50343499076 |
12 | 21337576122 |
13 | c3b49658b5 |
14 | 64524dd5c6 |
15 | 35d43de885 |
hex | 1e5d4b8c2a |
130414251050 has 48 divisors (see below), whose sum is σ = 255388788000. Its totient is φ = 49410187200.
The previous prime is 130414251043. The next prime is 130414251059. The reversal of 130414251050 is 50152414031.
It is a super-2 number, since 2×1304142510502 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (130414251059) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6155876 + ... + 6177024.
It is an arithmetic number, because the mean of its divisors is an integer number (5320599750).
Almost surely, 2130414251050 is an apocalyptic number.
130414251050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130414251050 is a deficient number, since it is larger than the sum of its proper divisors (124974536950).
130414251050 is a wasteful number, since it uses less digits than its factorization.
130414251050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27671 (or 27666 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 130414251050 its reverse (50152414031), we get a palindrome (180566665081).
The spelling of 130414251050 in words is "one hundred thirty billion, four hundred fourteen million, two hundred fifty-one thousand, fifty".
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