Base | Representation |
---|---|
bin | 1011110111001001011010… |
… | …1010000101111011101000 |
3 | 1201011210210202211212201202 |
4 | 2331302112222011323220 |
5 | 3202140103332434100 |
6 | 43423233450103332 |
7 | 2514154054444241 |
oct | 275622652057350 |
9 | 51153722755652 |
10 | 13042048327400 |
11 | 41791133034a4 |
12 | 156777771ab48 |
13 | 737b24206011 |
14 | 33134a66bcc8 |
15 | 1793c0dca7d5 |
hex | bdc96a85ee8 |
13042048327400 has 24 divisors (see below), whose sum is σ = 30322762361670. Its totient is φ = 5216819330880.
The previous prime is 13042048327393. The next prime is 13042048327403. The reversal of 13042048327400 is 472384024031.
It is a happy number.
It can be written as a sum of positive squares in 3 ways, for example, as 12641964246916 + 400084080484 = 3555554^2 + 632522^2 .
It is not an unprimeable number, because it can be changed into a prime (13042048327403) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 32605120619 + ... + 32605121018.
Almost surely, 213042048327400 is an apocalyptic number.
13042048327400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13042048327400 is an abundant number, since it is smaller than the sum of its proper divisors (17280714034270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13042048327400 is a wasteful number, since it uses less digits than its factorization.
13042048327400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65210241653 (or 65210241644 counting only the distinct ones).
The product of its (nonzero) digits is 129024, while the sum is 38.
The spelling of 13042048327400 in words is "thirteen trillion, forty-two billion, forty-eight million, three hundred twenty-seven thousand, four hundred".
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