Base | Representation |
---|---|
bin | 10010111110101111110… |
… | …010110000111101000000 |
3 | 11121200200121111022011221 |
4 | 102332233302300331000 |
5 | 132332224022124300 |
6 | 2435110502444424 |
7 | 163143242365246 |
oct | 22765762607500 |
9 | 4550617438157 |
10 | 1304324411200 |
11 | 463185143348 |
12 | 190953733714 |
13 | 95cc6cb2b35 |
14 | 471b5a28796 |
15 | 23ddd8cc31a |
hex | 12fafcb0f40 |
1304324411200 has 84 divisors (see below), whose sum is σ = 3210094745152. Its totient is φ = 521625484800.
The previous prime is 1304324411189. The next prime is 1304324411219. The reversal of 1304324411200 is 21144234031.
It is a super-3 number, since 3×13043244112003 (a number of 37 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8188315 + ... + 8346085.
Almost surely, 21304324411200 is an apocalyptic number.
1304324411200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1304324411200 is an abundant number, since it is smaller than the sum of its proper divisors (1905770333952).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1304324411200 is a wasteful number, since it uses less digits than its factorization.
1304324411200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162960 (or 162945 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1304324411200 its reverse (21144234031), we get a palindrome (1325468645231).
The spelling of 1304324411200 in words is "one trillion, three hundred four billion, three hundred twenty-four million, four hundred eleven thousand, two hundred".
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