130440011201320 has 96 divisors (see below), whose sum is σ = 312005354824800. Its totient is φ = 49061592542336.

The previous prime is 130440011201293. The next prime is 130440011201393. The reversal of 130440011201320 is 23102110044031.

It is a junction number, because it is equal to n+sod(n) for n = 130440011201291 and 130440011201300.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 50992762 + ... + 53489641.

It is an arithmetic number, because the mean of its divisors is an integer number (3250055779425).

Almost surely, 2^{130440011201320} is an apocalyptic number.

130440011201320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130440011201320 is an abundant number, since it is smaller than the sum of its proper divisors (181565343623480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130440011201320 is a wasteful number, since it uses less digits than its factorization.

130440011201320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104482519 (or 104482492 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 130440011201320 its reverse (23102110044031), we get a palindrome (153542121245351).

The spelling of 130440011201320 in words is "one hundred thirty trillion, four hundred forty billion, eleven million, two hundred one thousand, three hundred twenty".