Base | Representation |
---|---|
bin | 11101101010111001001100… |
… | …001110101000101011110110 |
3 | 122010000211000102122100012110 |
4 | 131222321030032220223312 |
5 | 114100431004133322100 |
6 | 1141310420530231450 |
7 | 36325443004632414 |
oct | 3552711416505366 |
9 | 563024012570173 |
10 | 130490975292150 |
11 | 3863aa03729090 |
12 | 12776037725586 |
13 | 57a7327ab1735 |
14 | 2431b229b82b4 |
15 | 1014582c6e250 |
hex | 76ae4c3a8af6 |
130490975292150 has 48 divisors (see below), whose sum is σ = 353037402249408. Its totient is φ = 31634175828000.
The previous prime is 130490975292109. The next prime is 130490975292203. The reversal of 130490975292150 is 51292579094031.
It is a super-3 number, since 3×1304909752921503 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 39542718136 + ... + 39542721435.
It is an arithmetic number, because the mean of its divisors is an integer number (7354945880196).
Almost surely, 2130490975292150 is an apocalyptic number.
130490975292150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130490975292150 is an abundant number, since it is smaller than the sum of its proper divisors (222546426957258).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130490975292150 is a wasteful number, since it uses less digits than its factorization.
130490975292150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79085439597 (or 79085439592 counting only the distinct ones).
The product of its (nonzero) digits is 6123600, while the sum is 57.
The spelling of 130490975292150 in words is "one hundred thirty trillion, four hundred ninety billion, nine hundred seventy-five million, two hundred ninety-two thousand, one hundred fifty".
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