Base | Representation |
---|---|
bin | 100110111001001… |
… | …0110000111011100 |
3 | 10100221200002000111 |
4 | 1031302112013130 |
5 | 10133042342140 |
6 | 333255335404 |
7 | 44224454212 |
oct | 11562260734 |
9 | 3327602014 |
10 | 1305043420 |
11 | 60a73248a |
12 | 305081564 |
13 | 17a4b2755 |
14 | c5474cb2 |
15 | 798897ea |
hex | 4dc961dc |
1305043420 has 96 divisors (see below), whose sum is σ = 2998114560. Its totient is φ = 475284480.
The previous prime is 1305043417. The next prime is 1305043429. The reversal of 1305043420 is 243405031.
It is a junction number, because it is equal to n+sod(n) for n = 1305043391 and 1305043400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1305043429) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1343535 + ... + 1344505.
It is an arithmetic number, because the mean of its divisors is an integer number (31230360).
Almost surely, 21305043420 is an apocalyptic number.
1305043420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1305043420, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1499057280).
1305043420 is an abundant number, since it is smaller than the sum of its proper divisors (1693071140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1305043420 is a wasteful number, since it uses less digits than its factorization.
1305043420 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1123 (or 1121 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 22.
The square root of 1305043420 is about 36125.3847038340. The cubic root of 1305043420 is about 1092.8024343053.
Adding to 1305043420 its reverse (243405031), we get a palindrome (1548448451).
The spelling of 1305043420 in words is "one billion, three hundred five million, forty-three thousand, four hundred twenty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •