Base | Representation |
---|---|
bin | 1011110111110111011100… |
… | …0101110111010011000110 |
3 | 1201012222200211112201020110 |
4 | 2331331313011313103012 |
5 | 3202340404312412340 |
6 | 43433035451213450 |
7 | 2515102202035305 |
oct | 275756705672306 |
9 | 51188624481213 |
10 | 13054403638470 |
11 | 4183383587587 |
12 | 156a045447286 |
13 | 739042b6327c |
14 | 331b9d53a43c |
15 | 179895933680 |
hex | bdf771774c6 |
13054403638470 has 128 divisors (see below), whose sum is σ = 33458609378304. Its totient is φ = 3251842159104.
The previous prime is 13054403638457. The next prime is 13054403638481. The reversal of 13054403638470 is 7483630445031.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 196886644 + ... + 196952936.
It is an arithmetic number, because the mean of its divisors is an integer number (261395385768).
Almost surely, 213054403638470 is an apocalyptic number.
13054403638470 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 13054403638470, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16729304689152).
13054403638470 is an abundant number, since it is smaller than the sum of its proper divisors (20404205739834).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13054403638470 is a wasteful number, since it uses less digits than its factorization.
13054403638470 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73006.
The product of its (nonzero) digits is 2903040, while the sum is 48.
The spelling of 13054403638470 in words is "thirteen trillion, fifty-four billion, four hundred three million, six hundred thirty-eight thousand, four hundred seventy".
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