Base | Representation |
---|---|
bin | 10011000001110000010… |
… | …000100001010101001000 |
3 | 11122000000122110210212002 |
4 | 103001300100201111020 |
5 | 132410332134441000 |
6 | 2440403132010132 |
7 | 163316251555526 |
oct | 23016020412510 |
9 | 4560018423762 |
10 | 1307553437000 |
11 | 464591911208 |
12 | 1914b5000948 |
13 | 963bcc750a5 |
14 | 4740080b316 |
15 | 2402c1108d5 |
hex | 13070421548 |
1307553437000 has 64 divisors (see below), whose sum is σ = 3060298800000. Its totient is φ = 522914750400.
The previous prime is 1307553436951. The next prime is 1307553437017. The reversal of 1307553437000 is 7343557031.
It is a happy number.
It is a super-2 number, since 2×13075534370002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4868219 + ... + 5129781.
It is an arithmetic number, because the mean of its divisors is an integer number (47817168750).
Almost surely, 21307553437000 is an apocalyptic number.
1307553437000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1307553437000 is an abundant number, since it is smaller than the sum of its proper divisors (1752745363000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1307553437000 is a wasteful number, since it uses less digits than its factorization.
1307553437000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 266583 (or 266569 counting only the distinct ones).
The product of its (nonzero) digits is 132300, while the sum is 38.
The spelling of 1307553437000 in words is "one trillion, three hundred seven billion, five hundred fifty-three million, four hundred thirty-seven thousand".
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