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131000004320400 = 24325236388890089
BaseRepresentation
bin11101110010010011010000…
…101110010001110010010000
3122011211110220112120012201200
4131302103100232101302100
5114132301002101223100
61142340323213031200
736410303141163435
oct3562232056216220
9564743815505650
10131000004320400
11388168763040a6
1212838818485500
13581332a704377
14244c61100bb8c
1510229263b4e00
hex7724d0b91c90

131000004320400 has 90 divisors (see below), whose sum is σ = 454606403894370. Its totient is φ = 34933334484480.

The previous prime is 131000004320399. The next prime is 131000004320441. The reversal of 131000004320400 is 4023400000131.

It can be written as a sum of positive squares in 3 ways, for example, as 35875390464 + 130964128929936 = 189408^2 + 11443956^2 .

It is a tau number, because it is divible by the number of its divisors (90).

It is a super-2 number, since 2×1310000043204002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 18194441445 + ... + 18194448644.

It is an arithmetic number, because the mean of its divisors is an integer number (5051182265493).

Almost surely, 2131000004320400 is an apocalyptic number.

131000004320400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131000004320400 is an abundant number, since it is smaller than the sum of its proper divisors (323606399573970).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000004320400 is a wasteful number, since it uses less digits than its factorization.

131000004320400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36388890113 (or 36388890099 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 18.

Adding to 131000004320400 its reverse (4023400000131), we get a palindrome (135023404320531).

The spelling of 131000004320400 in words is "one hundred thirty-one trillion, four million, three hundred twenty thousand, four hundred".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 16 18 20 24 25 30 36 40 45 48 50 60 72 75 80 90 100 120 144 150 180 200 225 240 300 360 400 450 600 720 900 1200 1800 3600 36388890089 72777780178 109166670267 145555560356 181944450445 218333340534 291111120712 327500010801 363888900890 436666681068 545833351335 582222241424 655000021602 727777801780 873333362136 909722252225 1091666702670 1310000043204 1455555603560 1637500054005 1746666724272 1819444504450 2183333405340 2620000086408 2729166756675 2911111207120 3275000108010 3638889008900 4366666810680 5240000172816 5458333513350 6550000216020 7277778017800 8187500270025 8733333621360 10916667026700 13100000432040 14555556035600 16375000540050 21833334053400 26200000864080 32750001080100 43666668106800 65500002160200 131000004320400