1310011320 has 32 divisors (see below), whose sum is σ = 3930034320. Its totient is φ = 349336320.

The previous prime is 1310011319. The next prime is 1310011331. The reversal of 1310011320 is 231100131.

1310011320 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1310011320² = 3432259317056284800, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 1310011296 and 1310011305.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5458261 + ... + 5458500.

Almost surely, 2^1310011320 is an apocalyptic number.

1310011320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1310011320 is an abundant number, since it is smaller than the sum of its proper divisors (2620023000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310011320 is a wasteful number, since it uses less digits than its factorization.

1310011320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10916775 (or 10916771 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

The square root of 1310011320 is about 36194.0785212167. The cubic root of 1310011320 is about 1094.1873330504.

Adding to 1310011320 its reverse (231100131), we get a palindrome (1541111451).

The spelling of 1310011320 in words is "one billion, three hundred ten million, eleven thousand, three hundred twenty".