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13100301300300 = 22352472333987551
BaseRepresentation
bin1011111010100010011011…
…0011100011001001001100
31201101101011112002111211120
42332220212303203021030
53204113404113102200
643510110105320540
72521315451523414
oct276504663431114
951341145074746
1013100301300300
1141a0896618205
121576b14496150
13740478a2c756
143340b50b7644
1517ab8008a9a0
hexbea26ce324c

13100301300300 has 144 divisors (see below), whose sum is σ = 38876143767552. Its totient is φ = 3404410688000.

The previous prime is 13100301300287. The next prime is 13100301300353. The reversal of 13100301300300 is 300310300131.

13100301300300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13100301300300.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1291525 + ... + 5279075.

It is an arithmetic number, because the mean of its divisors is an integer number (269973220608).

Almost surely, 213100301300300 is an apocalyptic number.

13100301300300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13100301300300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19438071883776).

13100301300300 is an abundant number, since it is smaller than the sum of its proper divisors (25775842467252).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100301300300 is a wasteful number, since it uses less digits than its factorization.

13100301300300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3987848 (or 3987841 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 13100301300300 its reverse (300310300131), we get a palindrome (13400611600431).

The spelling of 13100301300300 in words is "thirteen trillion, one hundred billion, three hundred one million, three hundred thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 47 50 60 75 94 100 141 150 188 233 235 282 300 466 470 564 699 705 932 940 1165 1175 1398 1410 2330 2350 2796 2820 3495 3525 4660 4700 5825 6990 7050 10951 11650 13980 14100 17475 21902 23300 32853 34950 43804 54755 65706 69900 109510 131412 164265 219020 273775 328530 547550 657060 821325 1095100 1642650 3285300 3987551 7975102 11962653 15950204 19937755 23925306 39875510 47850612 59813265 79751020 99688775 119626530 187414897 199377550 239253060 299066325 374829794 398755100 562244691 598132650 749659588 929099383 937074485 1124489382 1196265300 1858198766 1874148970 2248978764 2787298149 2811223455 3716397532 3748297940 4645496915 4685372425 5574596298 5622446910 9290993830 9370744850 11149192596 11244893820 13936490745 14056117275 18581987660 18741489700 23227484575 27872981490 28112234550 43667671001 46454969150 55745962980 56224469100 69682453725 87335342002 92909938300 131003013003 139364907450 174670684004 218338355005 262006026006 278729814900 436676710010 524012052012 655015065015 873353420020 1091691775025 1310030130030 2183383550050 2620060260060 3275075325075 4366767100100 6550150650150 13100301300300