Base | Representation |
---|---|
bin | 1011111010100010011011… |
… | …0011100011001001001100 |
3 | 1201101101011112002111211120 |
4 | 2332220212303203021030 |
5 | 3204113404113102200 |
6 | 43510110105320540 |
7 | 2521315451523414 |
oct | 276504663431114 |
9 | 51341145074746 |
10 | 13100301300300 |
11 | 41a0896618205 |
12 | 1576b14496150 |
13 | 740478a2c756 |
14 | 3340b50b7644 |
15 | 17ab8008a9a0 |
hex | bea26ce324c |
13100301300300 has 144 divisors (see below), whose sum is σ = 38876143767552. Its totient is φ = 3404410688000.
The previous prime is 13100301300287. The next prime is 13100301300353. The reversal of 13100301300300 is 300310300131.
13100301300300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 13100301300300.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1291525 + ... + 5279075.
It is an arithmetic number, because the mean of its divisors is an integer number (269973220608).
Almost surely, 213100301300300 is an apocalyptic number.
13100301300300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13100301300300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19438071883776).
13100301300300 is an abundant number, since it is smaller than the sum of its proper divisors (25775842467252).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100301300300 is a wasteful number, since it uses less digits than its factorization.
13100301300300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3987848 (or 3987841 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 13100301300300 its reverse (300310300131), we get a palindrome (13400611600431).
The spelling of 13100301300300 in words is "thirteen trillion, one hundred billion, three hundred one million, three hundred thousand, three hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •