Base | Representation |
---|---|
bin | 1111100111011… |
… | …11100001001101 |
3 | 100010111201101021 |
4 | 13303233201031 |
5 | 232014120433 |
6 | 20555514141 |
7 | 3150343204 |
oct | 763574115 |
9 | 303451337 |
10 | 131004493 |
11 | 67a48684 |
12 | 37a58951 |
13 | 211aaa69 |
14 | 1358223b |
15 | b77b22d |
hex | 7cef84d |
131004493 has 2 divisors, whose sum is σ = 131004494. Its totient is φ = 131004492.
The previous prime is 131004491. The next prime is 131004509. The reversal of 131004493 is 394400131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127170729 + 3833764 = 11277^2 + 1958^2 .
It is a cyclic number.
It is not a de Polignac number, because 131004493 - 21 = 131004491 is a prime.
Together with 131004491, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131004491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65502246 + 65502247.
It is an arithmetic number, because the mean of its divisors is an integer number (65502247).
Almost surely, 2131004493 is an apocalyptic number.
It is an amenable number.
131004493 is a deficient number, since it is larger than the sum of its proper divisors (1).
131004493 is an equidigital number, since it uses as much as digits as its factorization.
131004493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
The square root of 131004493 is about 11445.7194181930. The cubic root of 131004493 is about 507.8811140669.
The spelling of 131004493 in words is "one hundred thirty-one million, four thousand, four hundred ninety-three".
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