Base | Representation |
---|---|
bin | 11101110010011110101000… |
… | …111010101111100010011000 |
3 | 122011212122102222011020000020 |
4 | 131302132220322233202120 |
5 | 114133001012134314430 |
6 | 1142350103355310440 |
7 | 36411214656515064 |
oct | 3562365072574230 |
9 | 564778388136006 |
10 | 131012221401240 |
11 | 38820a75554823 |
12 | 1283b067a4b420 |
13 | 581452682399a |
14 | 244d04d7b6aa4 |
15 | 1022dddc15b10 |
hex | 7727a8eaf898 |
131012221401240 has 32 divisors (see below), whose sum is σ = 393036664204080. Its totient is φ = 34936592373632.
The previous prime is 131012221401239. The next prime is 131012221401241. The reversal of 131012221401240 is 42104122210131.
It is an interprime number because it is at equal distance from previous prime (131012221401239) and next prime (131012221401241).
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a self number, because there is not a number n which added to its sum of digits gives 131012221401240.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131012221401241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 545884255719 + ... + 545884255958.
Almost surely, 2131012221401240 is an apocalyptic number.
131012221401240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131012221401240 is an abundant number, since it is smaller than the sum of its proper divisors (262024442802840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131012221401240 is a wasteful number, since it uses less digits than its factorization.
131012221401240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1091768511691 (or 1091768511687 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 131012221401240 its reverse (42104122210131), we get a palindrome (173116343611371).
The spelling of 131012221401240 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-one million, four hundred one thousand, two hundred forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •