Base | Representation |
---|---|
bin | 10011000100001010101… |
… | …010111001100100101110 |
3 | 11122020201012011020121221 |
4 | 103010022222321210232 |
5 | 132431133333341220 |
6 | 2441512153413554 |
7 | 163440406423564 |
oct | 23041252714456 |
9 | 4566635136557 |
10 | 1310144043310 |
11 | 4656a1180063 |
12 | 191ab870a2ba |
13 | 967138a942b |
14 | 475a88c5a34 |
15 | 2412e7879aa |
hex | 1310aab992e |
1310144043310 has 32 divisors (see below), whose sum is σ = 2359730102400. Its totient is φ = 523730895648.
The previous prime is 1310144043281. The next prime is 1310144043323. The reversal of 1310144043310 is 133404410131.
It is a happy number.
It is a super-2 number, since 2×13101440433102 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 180880549 + ... + 180887791.
It is an arithmetic number, because the mean of its divisors is an integer number (73741565700).
Almost surely, 21310144043310 is an apocalyptic number.
1310144043310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1310144043310 is a deficient number, since it is larger than the sum of its proper divisors (1049586059090).
1310144043310 is a wasteful number, since it uses less digits than its factorization.
1310144043310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16032.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1310144043310 its reverse (133404410131), we get a palindrome (1443548453441).
The spelling of 1310144043310 in words is "one trillion, three hundred ten billion, one hundred forty-four million, forty-three thousand, three hundred ten".
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