Base | Representation |
---|---|
bin | 111101000000101101… |
… | …1010100101000000000 |
3 | 110112012001002002001010 |
4 | 1322001123110220000 |
5 | 4121312213121422 |
6 | 140105010440520 |
7 | 12315544245150 |
oct | 1720133245000 |
9 | 415161062033 |
10 | 131020442112 |
11 | 5062469541a |
12 | 21486593140 |
13 | c48041b431 |
14 | 64acc18760 |
15 | 361c731b0c |
hex | 1e816d4a00 |
131020442112 has 80 divisors (see below), whose sum is σ = 398910485952. Its totient is φ = 37434408960.
The previous prime is 131020442101. The next prime is 131020442131. The reversal of 131020442112 is 211244020131.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6082089 + ... + 6103592.
Almost surely, 2131020442112 is an apocalyptic number.
131020442112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131020442112 is an abundant number, since it is smaller than the sum of its proper divisors (267890043840).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131020442112 is an equidigital number, since it uses as much as digits as its factorization.
131020442112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12185709 (or 12185693 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 131020442112 its reverse (211244020131), we get a palindrome (342264462243).
The spelling of 131020442112 in words is "one hundred thirty-one billion, twenty million, four hundred forty-two thousand, one hundred twelve".
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