Base | Representation |
---|---|
bin | 1011111010101010101001… |
… | …1110010110011000100000 |
3 | 1201101120212110210010110211 |
4 | 2332222222132112120200 |
5 | 3204132420121214040 |
6 | 43511113220503504 |
7 | 2521424264153344 |
oct | 276525236263040 |
9 | 51346773703424 |
10 | 13102510335520 |
11 | 41a181a559051 |
12 | 157743024ab94 |
13 | 74073b5a5798 |
14 | 334244627624 |
15 | 17ac5de8e8ea |
hex | beaaa796620 |
13102510335520 has 96 divisors (see below), whose sum is σ = 31951051776000. Its totient is φ = 5073730016256.
The previous prime is 13102510335493. The next prime is 13102510335571. The reversal of 13102510335520 is 2553301520131.
13102510335520 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4382880 + ... + 6739039.
It is an arithmetic number, because the mean of its divisors is an integer number (332823456000).
Almost surely, 213102510335520 is an apocalyptic number.
13102510335520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13102510335520 is an abundant number, since it is smaller than the sum of its proper divisors (18848541440480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102510335520 is a wasteful number, since it uses less digits than its factorization.
13102510335520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11122170 (or 11122162 counting only the distinct ones).
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 13102510335520 its reverse (2553301520131), we get a palindrome (15655811855651).
The spelling of 13102510335520 in words is "thirteen trillion, one hundred two billion, five hundred ten million, three hundred thirty-five thousand, five hundred twenty".
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