Base | Representation |
---|---|
bin | 11101110010101111011000… |
… | …100110001111000111001100 |
3 | 122011221100212000022200122120 |
4 | 131302233120212033013030 |
5 | 114133244323001413400 |
6 | 1142402235441012540 |
7 | 36412422351345465 |
oct | 3562573046170714 |
9 | 564840760280576 |
10 | 131030201201100 |
11 | 3882866169a553 |
12 | 12842645324150 |
13 | 5816130800a06 |
14 | 244dc77665d6c |
15 | 10235e242dca0 |
hex | 772bd898f1cc |
131030201201100 has 144 divisors (see below), whose sum is σ = 387296124461568. Its totient is φ = 34187723413760.
The previous prime is 131030201201093. The next prime is 131030201201101. The reversal of 131030201201100 is 1102102030131.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 131030201201100.
It is not an unprimeable number, because it can be changed into a prime (131030201201101) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 45804454 + ... + 48580946.
It is an arithmetic number, because the mean of its divisors is an integer number (2689556419872).
Almost surely, 2131030201201100 is an apocalyptic number.
131030201201100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131030201201100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (193648062230784).
131030201201100 is an abundant number, since it is smaller than the sum of its proper divisors (256265923260468).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131030201201100 is a wasteful number, since it uses less digits than its factorization.
131030201201100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2779904 (or 2779897 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 131030201201100 its reverse (1102102030131), we get a palindrome (132132303231231).
The spelling of 131030201201100 in words is "one hundred thirty-one trillion, thirty billion, two hundred one million, two hundred one thousand, one hundred".
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